Source
FractalTriangles.java - JAVA Applet
List of numbers
- f(n,k) = f(n-1,k-1) + f(n-1,k) mod M - Pascal Triangle
- f(n,k) = f(n-1,k-1) + (n-1)*f(n-1,k) mod M - First Kind of Stirling Numbers
- f(n,k) = f(n-1,k-1) + k*f(n-1,k) mod M - Second Kind of Stirling Numbers
- f(n,k) = (n-k)*f(n-1,k-1) + (k+1)*f(n-1,k) mod M, (for n==k f(n,k)=0) - First Kind of Euler Numbers
- f(n,k) = (2*n-k-1)*f(n-1,k-1) + (k+1)*f(n-1,k) mod M, (for n==k f(n,k)=0) - Second Kind of Euler Numbers
- f(n,k) = f(n-1,k-1) + f(n-1,k)*f(n-1,k) mod M
- f(n,k) = f(n-1,k-1)*f(n-1,k-1) + f(n-1,k) mod M
- f(n,k) = f(n-1,k-1)*f(n-1,k-1) + f(n-1,k)*f(n-1,k) mod M
- f(n,k) = (n-1)*f(n-1,k-1) + (k+1)*f(n-1,k) mod M
- f(n,k) = (n+1)*f(n-1,k-1) + (k-1)*f(n-1,k) mod M
- f(n,k) = f[n-k-1)*f(n-1,k-1) + f[k+1)*f(n-1,k) mod M
- f(n,k) = (f[n-k+1)*f(n-1,k-1) + f[k-1)*f(n-1,k)) mod M
- f(n,k) = f(n-1,k-1) + f[k)*f(n-1,k) mod M
- f(n,k) = f(n-1,k-1) + f[n)*f(n-1,k) mod M
- f(n,k) = f(n-1,k+1) + f(n-1,k) + f(n-1,k-1) mod M
- f(n,k) = f(n-1,k+1) + f(n-1,k-1) mod M
- for (n > 1) f(n,k) = f(n-1,k+1) + f(n-2,k) + f(n-1,k-1) mod M
else f(n,k) = f(n-1,k+1) + mod + f(n-1,k-1) mod M
- f(n,k) = f(n-1,k-1)^f(n-1,k) + f(n-1,k)^f(n-1,k-1) mod M
I found error here, see left triangle.
- f(n,k) = f(n-1,k-1) + f(n-1,k)^f(n-1,k-1) mod M
- f(n,k) = f(n-1,k) + f(n-1,k)^f(n-1,k-1) mod M
- f(n,k) = f(n-1,k) + (f(n-1,k-1)^f(n-1,k) mod k) mod M
- f(n,k) = f(n-1,k) + (f(n-1,k-1)^f(n-1,k) mod n) mod M
- f(n,k) = f(n-1,k) + (f(n-1,k-1)^f(n-1,k) mod M-f(n-1,k-1)) mod M
- f(n,k) = f(n-1,k) + (f(n-1,k-1)^f(n-1,k) mod M-f(n-1,k)) mod M
For each of numbers we assumed:
f(n,n) = 1
f(n,k) = 0 for n<k
f(n,0) = δn,0
f(0,k) = δ0,k